## Phasor Diagram

Consider a transformer supplying the load as shown in Fig. 1.

Â Â Â Â Â Â The various transformer parameters are,

R_{1 }= Primary winding resistance

X_{1 }= Primary leakage reactance

R_{2 }= Secondary winding resistance

X_{2 }= Secondary leakage reactance

Z_{L }= Load impedance

I_{1}= Primary current

I_{2 }= Secondary current = I_{L }= Load current

now Äª_{1} = Äª_{o} + Äª_{2}‘

where I_{o }= No load current

I_{2}‘= Load component of current decided by the load

= K I_{2} where K is the transformer component

The primary voltage V_{1 }has now three components,1. -E_{1}, the induced e.m.f. which opposes V_{1}

2. I_{1} R_{1}, the drop across the resistance, in phase with I_{1}

3. I_{1} X_{1}, the drop across the reactance, leading I_{1} by 90^{o}

The secondary induced e.m.f. has also three components,

1. V_{2}, the terminal voltage across the load

2. I_{2} R_{2}, the drop across the resistance, in phase with I_{2}

3. I_{2} X_{2}, the drop across the reactance, leading I_{2} by 90^{o}

The phasor diagram for the transformer on load depends on the nature of the load power factor. Let us consider the various cases of the load power factor.

1.1 Unity power factor load, cosÎ¦_{2} = 1 As load power factor is unity, the voltage V_{2 }and I_{2 }are in phase. The steps to draw the phasor diagram are,

1. Consider flux Î¦ as a reference

2. E1 lags Î¦ by 90o. Reverse E1 to get -E1.

3. E1 and E2 are inphase

4. Assume V2 is in a particular direction

5. I_{2 }is in phase with V_{2}.

6. Add I_{2 }R_{2 }and I_{2 }X_{2 }to to get E_{2}.

7. Reverse I_{2 }to get I_{2}**‘**.

8. Add I_{o }and I_{2}**‘** to get I_{1}.

9. Add I_{1 }R_{1 }and to -E_{1 }to get V_{1}.

The angle between V1 and I1 is Î¦1 and cosÎ¦1 is the primary power factor. Remember that I1X1 leads I1 direction by 90o and I2 X2 leads I2 by 90o as current through inductance lags voltage across inductance by 90o. The phasor diagram is shown in Fig.2

Lagging Power Factor Load, cos Î¦_{2:}

Â Â Â Â Â Â As the load power factor is lagging cosÎ¦2, the current I2Â lags V2Â by angle Î¦2. So the only change in drawing the phasor diagram is to draw I2Â laggingÂ V2Â by Î¦2Â in step 5 discussed earlier. Accordingly direction of I2Â R2, I2Â X2, I2′, I1, I1Â R1Â and I1X1Â will change. Remember that whatever may be the power factor of load, I2X2Â leads I2Â by 90oÂ and I1X1Â leads I1Â by 90o.Â Â Â Â Â Â The complete phasor diagram is shown in Fig. 3.

Loading Power Factor Load, cos Î¦_{2:}

As the load power factor is leading, the current I2 leads V2 by angle Î¦2. So change is to draw I2 leading I2 by angle Î¦2. All other steps remain the same as before. The complete phasor diagram is shown in Fig. 4